Optimal. Leaf size=103 \[ \frac {a (b c-a d)^2 x}{b^2 \left (a^2+b^2\right )}+\frac {d (2 b c-a d) x}{b^2}-\frac {d^2 \log (\cos (e+f x))}{b f}+\frac {(b c-a d)^2 \log (a \cos (e+f x)+b \sin (e+f x))}{b \left (a^2+b^2\right ) f} \]
[Out]
________________________________________________________________________________________
Rubi [A]
time = 0.08, antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 4, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {3622, 3556,
3565, 3611} \begin {gather*} \frac {(b c-a d)^2 \log (a \cos (e+f x)+b \sin (e+f x))}{b f \left (a^2+b^2\right )}+\frac {a x (b c-a d)^2}{b^2 \left (a^2+b^2\right )}+\frac {d x (2 b c-a d)}{b^2}-\frac {d^2 \log (\cos (e+f x))}{b f} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
Rule 3556
Rule 3565
Rule 3611
Rule 3622
Rubi steps
\begin {align*} \int \frac {(c+d \tan (e+f x))^2}{a+b \tan (e+f x)} \, dx &=\frac {d (2 b c-a d) x}{b^2}+\frac {d^2 \int \tan (e+f x) \, dx}{b}+\frac {(b c-a d)^2 \int \frac {1}{a+b \tan (e+f x)} \, dx}{b^2}\\ &=\frac {a (b c-a d)^2 x}{b^2 \left (a^2+b^2\right )}+\frac {d (2 b c-a d) x}{b^2}-\frac {d^2 \log (\cos (e+f x))}{b f}+\frac {(b c-a d)^2 \int \frac {b-a \tan (e+f x)}{a+b \tan (e+f x)} \, dx}{b \left (a^2+b^2\right )}\\ &=\frac {a (b c-a d)^2 x}{b^2 \left (a^2+b^2\right )}+\frac {d (2 b c-a d) x}{b^2}-\frac {d^2 \log (\cos (e+f x))}{b f}+\frac {(b c-a d)^2 \log (a \cos (e+f x)+b \sin (e+f x))}{b \left (a^2+b^2\right ) f}\\ \end {align*}
________________________________________________________________________________________
Mathematica [C] Result contains complex when optimal does not.
time = 0.17, size = 108, normalized size = 1.05 \begin {gather*} \frac {\frac {(c+i d)^2 \log (i-\tan (e+f x))}{i a-b}-\frac {(c-i d)^2 \log (i+\tan (e+f x))}{i a+b}+\frac {2 (b c-a d)^2 \log (a+b \tan (e+f x))}{b \left (a^2+b^2\right )}}{2 f} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A]
time = 0.20, size = 117, normalized size = 1.14
method | result | size |
derivativedivides | \(\frac {\frac {\left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right ) \ln \left (a +b \tan \left (f x +e \right )\right )}{\left (a^{2}+b^{2}\right ) b}+\frac {\frac {\left (2 a c d -b \,c^{2}+b \,d^{2}\right ) \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2}+\left (a \,c^{2}-a \,d^{2}+2 b c d \right ) \arctan \left (\tan \left (f x +e \right )\right )}{a^{2}+b^{2}}}{f}\) | \(117\) |
default | \(\frac {\frac {\left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right ) \ln \left (a +b \tan \left (f x +e \right )\right )}{\left (a^{2}+b^{2}\right ) b}+\frac {\frac {\left (2 a c d -b \,c^{2}+b \,d^{2}\right ) \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2}+\left (a \,c^{2}-a \,d^{2}+2 b c d \right ) \arctan \left (\tan \left (f x +e \right )\right )}{a^{2}+b^{2}}}{f}\) | \(117\) |
norman | \(\frac {\left (a \,c^{2}-a \,d^{2}+2 b c d \right ) x}{a^{2}+b^{2}}+\frac {\left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right ) \ln \left (a +b \tan \left (f x +e \right )\right )}{\left (a^{2}+b^{2}\right ) b f}+\frac {\left (2 a c d -b \,c^{2}+b \,d^{2}\right ) \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2 f \left (a^{2}+b^{2}\right )}\) | \(120\) |
risch | \(\frac {2 i x c d}{i b -a}-\frac {x \,c^{2}}{i b -a}+\frac {x \,d^{2}}{i b -a}-\frac {2 i a^{2} d^{2} x}{\left (a^{2}+b^{2}\right ) b}-\frac {2 i a^{2} d^{2} e}{\left (a^{2}+b^{2}\right ) b f}+\frac {4 i a c d x}{a^{2}+b^{2}}+\frac {4 i a c d e}{\left (a^{2}+b^{2}\right ) f}-\frac {2 i b \,c^{2} x}{a^{2}+b^{2}}-\frac {2 i b \,c^{2} e}{\left (a^{2}+b^{2}\right ) f}+\frac {2 i d^{2} x}{b}+\frac {2 i d^{2} e}{b f}+\frac {\ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {i b +a}{i b -a}\right ) a^{2} d^{2}}{\left (a^{2}+b^{2}\right ) b f}-\frac {2 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {i b +a}{i b -a}\right ) a c d}{\left (a^{2}+b^{2}\right ) f}+\frac {b \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {i b +a}{i b -a}\right ) c^{2}}{\left (a^{2}+b^{2}\right ) f}-\frac {d^{2} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )}{b f}\) | \(357\) |
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [A]
time = 0.56, size = 126, normalized size = 1.22 \begin {gather*} \frac {\frac {2 \, {\left (a c^{2} + 2 \, b c d - a d^{2}\right )} {\left (f x + e\right )}}{a^{2} + b^{2}} + \frac {2 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (b \tan \left (f x + e\right ) + a\right )}{a^{2} b + b^{3}} - \frac {{\left (b c^{2} - 2 \, a c d - b d^{2}\right )} \log \left (\tan \left (f x + e\right )^{2} + 1\right )}{a^{2} + b^{2}}}{2 \, f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [A]
time = 0.70, size = 133, normalized size = 1.29 \begin {gather*} -\frac {{\left (a^{2} + b^{2}\right )} d^{2} \log \left (\frac {1}{\tan \left (f x + e\right )^{2} + 1}\right ) - 2 \, {\left (a b c^{2} + 2 \, b^{2} c d - a b d^{2}\right )} f x - {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (\frac {b^{2} \tan \left (f x + e\right )^{2} + 2 \, a b \tan \left (f x + e\right ) + a^{2}}{\tan \left (f x + e\right )^{2} + 1}\right )}{2 \, {\left (a^{2} b + b^{3}\right )} f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [C] Result contains complex when optimal does not.
time = 0.64, size = 1025, normalized size = 9.95 \begin {gather*} \begin {cases} \frac {\tilde {\infty } x \left (c + d \tan {\left (e \right )}\right )^{2}}{\tan {\left (e \right )}} & \text {for}\: a = 0 \wedge b = 0 \wedge f = 0 \\\frac {c^{2} x + \frac {c d \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{f} - d^{2} x + \frac {d^{2} \tan {\left (e + f x \right )}}{f}}{a} & \text {for}\: b = 0 \\\frac {i c^{2} f x \tan {\left (e + f x \right )}}{2 b f \tan {\left (e + f x \right )} - 2 i b f} + \frac {c^{2} f x}{2 b f \tan {\left (e + f x \right )} - 2 i b f} + \frac {i c^{2}}{2 b f \tan {\left (e + f x \right )} - 2 i b f} + \frac {2 c d f x \tan {\left (e + f x \right )}}{2 b f \tan {\left (e + f x \right )} - 2 i b f} - \frac {2 i c d f x}{2 b f \tan {\left (e + f x \right )} - 2 i b f} - \frac {2 c d}{2 b f \tan {\left (e + f x \right )} - 2 i b f} + \frac {i d^{2} f x \tan {\left (e + f x \right )}}{2 b f \tan {\left (e + f x \right )} - 2 i b f} + \frac {d^{2} f x}{2 b f \tan {\left (e + f x \right )} - 2 i b f} + \frac {d^{2} \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )} \tan {\left (e + f x \right )}}{2 b f \tan {\left (e + f x \right )} - 2 i b f} - \frac {i d^{2} \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{2 b f \tan {\left (e + f x \right )} - 2 i b f} - \frac {i d^{2}}{2 b f \tan {\left (e + f x \right )} - 2 i b f} & \text {for}\: a = - i b \\- \frac {i c^{2} f x \tan {\left (e + f x \right )}}{2 b f \tan {\left (e + f x \right )} + 2 i b f} + \frac {c^{2} f x}{2 b f \tan {\left (e + f x \right )} + 2 i b f} - \frac {i c^{2}}{2 b f \tan {\left (e + f x \right )} + 2 i b f} + \frac {2 c d f x \tan {\left (e + f x \right )}}{2 b f \tan {\left (e + f x \right )} + 2 i b f} + \frac {2 i c d f x}{2 b f \tan {\left (e + f x \right )} + 2 i b f} - \frac {2 c d}{2 b f \tan {\left (e + f x \right )} + 2 i b f} - \frac {i d^{2} f x \tan {\left (e + f x \right )}}{2 b f \tan {\left (e + f x \right )} + 2 i b f} + \frac {d^{2} f x}{2 b f \tan {\left (e + f x \right )} + 2 i b f} + \frac {d^{2} \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )} \tan {\left (e + f x \right )}}{2 b f \tan {\left (e + f x \right )} + 2 i b f} + \frac {i d^{2} \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{2 b f \tan {\left (e + f x \right )} + 2 i b f} + \frac {i d^{2}}{2 b f \tan {\left (e + f x \right )} + 2 i b f} & \text {for}\: a = i b \\\frac {x \left (c + d \tan {\left (e \right )}\right )^{2}}{a + b \tan {\left (e \right )}} & \text {for}\: f = 0 \\\frac {2 a^{2} d^{2} \log {\left (\frac {a}{b} + \tan {\left (e + f x \right )} \right )}}{2 a^{2} b f + 2 b^{3} f} + \frac {2 a b c^{2} f x}{2 a^{2} b f + 2 b^{3} f} - \frac {4 a b c d \log {\left (\frac {a}{b} + \tan {\left (e + f x \right )} \right )}}{2 a^{2} b f + 2 b^{3} f} + \frac {2 a b c d \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{2 a^{2} b f + 2 b^{3} f} - \frac {2 a b d^{2} f x}{2 a^{2} b f + 2 b^{3} f} + \frac {2 b^{2} c^{2} \log {\left (\frac {a}{b} + \tan {\left (e + f x \right )} \right )}}{2 a^{2} b f + 2 b^{3} f} - \frac {b^{2} c^{2} \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{2 a^{2} b f + 2 b^{3} f} + \frac {4 b^{2} c d f x}{2 a^{2} b f + 2 b^{3} f} + \frac {b^{2} d^{2} \log {\left (\tan ^{2}{\left (e + f x \right )} + 1 \right )}}{2 a^{2} b f + 2 b^{3} f} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A]
time = 0.57, size = 127, normalized size = 1.23 \begin {gather*} \frac {\frac {2 \, {\left (a c^{2} + 2 \, b c d - a d^{2}\right )} {\left (f x + e\right )}}{a^{2} + b^{2}} - \frac {{\left (b c^{2} - 2 \, a c d - b d^{2}\right )} \log \left (\tan \left (f x + e\right )^{2} + 1\right )}{a^{2} + b^{2}} + \frac {2 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left ({\left | b \tan \left (f x + e\right ) + a \right |}\right )}{a^{2} b + b^{3}}}{2 \, f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Mupad [B]
time = 5.73, size = 115, normalized size = 1.12 \begin {gather*} \frac {\ln \left (\mathrm {tan}\left (e+f\,x\right )-\mathrm {i}\right )\,\left (-c^2\,1{}\mathrm {i}+2\,c\,d+d^2\,1{}\mathrm {i}\right )}{2\,f\,\left (a+b\,1{}\mathrm {i}\right )}+\frac {\ln \left (\mathrm {tan}\left (e+f\,x\right )+1{}\mathrm {i}\right )\,\left (-c^2+c\,d\,2{}\mathrm {i}+d^2\right )}{2\,f\,\left (b+a\,1{}\mathrm {i}\right )}+\frac {\ln \left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right )\,{\left (a\,d-b\,c\right )}^2}{b\,f\,\left (a^2+b^2\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________